博客
关于我
2019ICPC 沈阳重现 L-Flowers(二分)
阅读量:390 次
发布时间:2019-03-05

本文共 1012 字,大约阅读时间需要 3 分钟。

7-7 L-Flowers

Recently Jack becomes much more romantic. He would like to prepare several bunches of flowers.

Each bunch of flowers must have exactly M flowers. As Jack does not want to be boring, he hopes that flowers in the same bunch are all different species. Now there are N species of flowers in the flower shop, and the number of the i-th species of flower is a​i. Now Jack would like to know how many bunches of flowers he can prepare at most.

(Flowers are used to propose.)

Sample Input
1
5 3
1 1 1 2 1

Sample Output

2
思路:二分答案,看一下共x朵花,每朵花m个不同的花组成能不能满足就行了。

#include
using namespace std;typedef long long ll;const int maxn=3e5+1; int T,n;ll k,a[maxn];bool check(ll x){ ll sum=0; for(int i=1;i<=n;++i) sum+=min(a[i],x); return sum>=x*k;}int main(){ scanf("%d",&T); while(T--) { ll sum=0; scanf("%d %lld",&n,&k); for(int i=1;i<=n;++i) scanf("%lld",&a[i]),sum+=a[i]; ll l=0,r=sum,mid; while(l<=r) { mid=(l+r)>>1; if(check(mid)) l=mid+1; else r=mid-1; } printf("%lld\n",r); } }

转载地址:http://thewz.baihongyu.com/

你可能感兴趣的文章
MySQL-Buffer的应用
查看>>
mysql-cluster 安装篇(1)---简介
查看>>
mysql-connector-java.jar乱码,最新版mysql-connector-java-8.0.15.jar,如何愉快的进行JDBC操作...
查看>>
mysql-connector-java各种版本下载地址
查看>>
mysql-EXPLAIN
查看>>
MySQL-Explain的详解
查看>>
mysql-group_concat
查看>>
MySQL-redo日志
查看>>
MySQL-【1】配置
查看>>
MySQL-【4】基本操作
查看>>
Mysql-丢失更新
查看>>
Mysql-事务阻塞
查看>>
Mysql-存储引擎
查看>>
mysql-开启慢查询&所有操作记录日志
查看>>
MySQL-数据目录
查看>>
MySQL-数据页的结构
查看>>
MySQL-架构篇
查看>>
MySQL-索引的分类(聚簇索引、二级索引、联合索引)
查看>>
Mysql-触发器及创建触发器失败原因
查看>>
MySQL-连接
查看>>